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2 years ago

Please solve for me

Mathematics

1 answer:

kondaur [170]2 years ago

7 0

Answer:

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Step-by-step explanation:

Szjnznz s8sbbsnsjs

Mzmzmznzm

Mzmsmxmx

Mzmxmkx

Km mmx

Zkskms

Kzmz

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A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What

gizmo_the_mogwai [7]

Answer:

1) The slope of the line segment AB is $\frac{4}{3}$ .

2) The length of the line segment AB is 10.

3) The coordinates of the midpoint of the line segment AB is $M(x,y) = (5,7)$ .

4) The slope of a line perpendicular to line segment AB is $-\frac{3}{4}$ .

Step-by-step explanation:

1) Let $A(x,y) = (2,3)$ and $B(x,y) = (8,11)$ . From Analytical Geometry, we get that slope of AB ( $m_{AB}$ ), dimensionless, is determined by the following formula:

$m_{AB} = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (1)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the slope of the line segment is:

$m_{AB} = \frac{11-3}{8-2}$

$m_{AB} = \frac{4}{3}$

The slope of the line segment AB is $\frac{4}{3}$ .

2) The length of the line segment AB ( $l_{AB}$ ), dimensionless, can be calculated by the Pythagorean Theorem:

$l_{AB} =\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}}$ (2)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the length of the line segment AB is:

$l_{AB} = \sqrt{(8-2)^{2}+(11-3)^{2}}$

$l_{AB} = 10$

The length of the line segment AB is 10.

3) The coordinates of the midpoint of the line segment AB are, respectively:

$x_{M} = \frac{x_{A}+x_{B}}{2}$ (3)

$y_{M} = \frac{y_{A}+y_{B}}{2}$ (4)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the coordinates of the midpoint of the line segment AB are, respectively:

$x_{M} = \frac{2+8}{2}$

$x_{M} = 5$

$y_{M} = \frac{3+11}{2}$

$y_{M} = 7$

The coordinates of the midpoint of the line segment AB is $M(x,y) = (5,7)$ .

4) From Analytical Geometry we can determine the slope of a line perpendicular to line segment AB as a function of the slope of the line segment:

$m_{\perp} = -\frac{1}{m_{AB}}$ (5)

If we know that $m_{AB} = \frac{4}{3}$ , then the slope of a line perpendicular to AB is:

$m_{\perp} = - \frac{1}{\frac{4}{3} }$

$m_{\perp} = -\frac{3}{4}$

The slope of a line perpendicular to line segment AB is $-\frac{3}{4}$ .

7 0

3 years ago

Margaret is saving money for her

EleoNora [17]

I mean sorry for answer but it’s order decimal form but for fraction form you were right it 4/10

6 0

3 years ago

Fifty- five percent of the students at west side middle school walk to school. What fraction of the students walk to school

wel

Answer:

55/100 is equivalent to 55% but the fraction in lower terms or simplified is 11/20 hope i helped!

Step-by-step explanation:

7 0

2 years ago

a girl was asked about her age and she said she is half her mothers age and she was asked how old was her mother and she said i

Vlad [161]

Answer:

The girl is 19 y/o, the mom is 38 y/o and the dad is 43 y/o.

Step-by-step explanation:

26+13+31= 70 NO

40+20+45= 105 NOT QUITE

19+38+43= 100 YES

7 0

2 years ago

Read 2 more answers

The function below can be used to calculate the cost of making a long distance call, f(m), which is based on a $2.50 initial cha

Vera_Pavlovna [14]

F(m) = 2.5 + 0.12m

if Natalie paid $6.82

6.82 = 2.5 + 0.12m
0.12m = 6.82 - 2.5
0.12m = 4.32
m = 4.32 ÷ 0.12
m = 36

The call was 36 minutes long.

5 0

3 years ago

Please solve for me ​

Please solve for me