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4 years ago

If two parallel lines are cut by a transversal, then would the same side interior angles ever be congruent?

Mathematics

1 answer:

Sholpan [36]4 years ago

6 0

Answer:

Step-by-step explanation:

Yes!

If the traversal is perpendicular to the parallel lines.

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Please help!!!!!!!!!

RoseWind [281]

Answer:

=7.071068

Step-by-step explanation

subtract the x values and y values and square them then add them together and find it's square root

4 0

3 years ago

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Anyone mind giving me a helping hand hope you have a good day!!!

Yanka [14]

Answer:

The last option

Step-by-step explanation:

The last option

8 0

3 years ago

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Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th

NeX [460]

As long as Loren drove, the law of motion was

$200 = st_1 \implies t_1 = \dfrac{200}{s}$

As long as Loid drove, the law of motion was

$100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}$

So, the total time they took is

$t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}$

Had Loren driven the whole time, the law of motion would have been

$300=st_3 \implies t_3 = \dfrac{300}{s}$

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

$t_3 = t_1+t_2-0.5$

This translates into

$\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}$

If we subtract 200/s from both sides, we have

$\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}$

We can simplify the right hand side by summing the two fractions:

$\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}$

So, we have to solve

$\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}$

If we cross multiply the denominators, we have

$200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0$

Which yields the solutions

$s=-40,\quad s=50$

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0

3 years ago

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If you’re good with probability math 30 please help with questions 33 and 35! real answers only

drek231 [11]

Answer: 33) b 34) a 35) none

Step-by-step explanation:

33)

Filling in the Venn Diagram (from Left to right, including outside of circles):

T only = 13

(T ∩ F)only = 6

F only = 21

(T ∩ D) only = 3

T ∩ F ∩ D = 5

(F ∩ D) only = 8

D only = 15

(T ∪ F ∪ D)' = 11

TOTAL = 82

$P(D'\cap F) = \dfrac{6+21}{13+6+21+3+5+8+15+11}\quad =\large\boxed{\dfrac{27}{82}}$

34)

Red = 26

Face = 12

Red ∩ Face = 6

Total cards = 52

R ∪ F = R + F - (R ∩ F)

= 26 + 12 - 6

= 32

$P(R\cup F)=\dfrac{R\cup F}{Total}\quad =\dfrac{32}{52}\quad \rightarrow \quad \large\boxed{\dfrac{8}{13}}$

35) Note that the total is 34 + 17 + 8 + 3 + 9 + 4 + 5 = 80

I think the teacher made an error, if so, then the answer is "d".

$P(C) = \dfrac{34+17+3+9}{Total} =\dfrac{53}{80}\quad \bigg(not\ \dfrac{34}{75}\bigg)\qquad \text{This is False.}\\\\\\P(S\cap T)=\dfrac{9+0}{Total}=\dfrac{9}{80}\quad \bigg(not\ \dfrac{12}{75}\bigg)\qquad \text{This is False.}\\\\\\\\P(C\cup T)\cup S = \dfrac{17+9+3+4}{Total}= \dfrac{33}{80}\quad \bigg(not\ \dfrac{38}{75}\bigg)\qquad \text{This is False.}\\\\\\P(C\cup T)\cap S'=\dfrac{34+17+8}{Total}=\dfrac{59}{80}\quad \bigg(not\ \dfrac{59}{75}\bigg)\quad \text{This is False.}$

7 0

3 years ago

The Tire on franks bike moves 75 inches in one rotation. How many rotations will the tire have made after frank rides 50 feet

kifflom [539]

8 rotations. first must convert 50 ft into inches. 50x12=600 in. If you know the distance and the length of rotation, divide the length (600) by the length of each rotation (75) and you get 8

7 0

4 years ago

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