Select the statement that describes this expression: (10 − 3) x 4 + 5.

2 answers:

8 0

It would definitely be the 3rd one! Use PEMDAS to help you find the order of things, Parentheses, Exponent, Multiply, Divide, Add, Subtract.

k0ka [10]3 years ago

7 0

3rd choice ~ Multiply 4 by the difference of 10 and 3, then add 5

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tamara has completed 60% of her practice time for the track meet. If she is expected to practice for 18h, how long has she alrea

anyanavicka [17]

Answer:

10h and 48min

Step-by-step explanation:

60*18=1080

1080/100=10.8

so 10.8h which means 10 hours and 48 min

4 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :