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Pavlova-9 [17]
3 years ago
5

Expressions in 1 variable if x=144. Problem:1/4x-7

Mathematics
1 answer:
Vikentia [17]3 years ago
8 0
The answer to this question is 29
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Ryan's unpaid credit card balance was $1853.68. His APR is 24.9%. What is his new balance after he makes one new transaction for
nataly862011 [7]

Answer:

  $2070.14

Step-by-step explanation:

Credit card terms vary, as do methods of computing interest and new balance. Here, we'll assume that no payment has been made (<em>in violation of the terms of the credit card</em>), and that the finance charge is only applied to the previous balance.

The finance charge is ...

  $1853.68 × 0.249 ÷ 12 = $38.46 . . . . . . . the monthly rate is 0.249÷12

Then the new balance will be the sum of the previous balance, finance charge, and new transaction(s):

  $1853.68 +38.46 + 178.00 = $2070.14

_____

<em>Comment on lack of payment</em>

Because no payment has been made, there may also be a late-payment charge added to the balance.

4 0
3 years ago
What is the solution to x 4 + 4x 3 ≤ 12x 2?
andriy [413]

Answer:

-6,2

Step-by-step explanation:

im not sure what the answer is

4 0
3 years ago
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For f(x) = 3x + 1 and g(x) = x^2 - 7, find f(g(4)).
kodGreya [7K]

First, let's find g(4). After we find it, we can substitute the value into f(x).


To find g(4), we need to substitute x = 4 into the function g(x), as shown below:

g(x) = x^2 - 7

g(4) = 4^2 - 7

g(4) = 9


Now that we have found g(4) = 9, we can substitute this value in for x in f(x).

f(x) = 3x + 1

f(9) = 3(9) + 1

f(9) = 28


f(g(4)) is equal to 28.

4 0
3 years ago
What type of conic section is the following equation? x2 + (y - 5)2 = 12 parabola circle hyperbola ellipse
chubhunter [2.5K]

Answer: Circle

Step-by-step explanation:

It is a circle.

Center: (0,5)

r= √12 =2√3

7 0
3 years ago
Simplify (4x − 6) + (3x + 6). (1 point) 7x 7x − 12 x 7x + 12
bija089 [108]

Answer:

7x for the first one and −5x^8+12 for the second one

Step-by-step explanation:

please mark me brainliest :)

7 0
3 years ago
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