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tensa zangetsu [6.8K]
3 years ago
5

25. In the year 2016, the population of Johns Creek was 124,000. Statistics show that the population is

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Answer:

6 years

Step-by-step explanation:

1 year

124,000 x .0734

133,101.6

2 years

133,101.6 x .0734

142,871.3

3 years

142,871.3 x .0734

153,358.1

4 years

153,358.1 x .0734

164,614.6

5 years

164,614.6 x .0734

176,697.3

6 years

176,697.3 x .0734

189,666.9

Aliun [14]3 years ago
3 0
Bhguugggggg hghjjjbgg. bbbh
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Line V has a slope of 8/9. Line w is perpendicular to V. What is the slope of line W?
Alex787 [66]

Answer:

W = -9/8

Step-by-step explanation:

for two perpendicular lines

W*V = -1

W = 9/8*(-1)

W= -9/8

6 0
3 years ago
A cylinder has a volume of 90pi and a radius of 3. what is the height?
kykrilka [37]

Step-by-step explanation:

  • volume of cylinder=90π
  • πr²h=90π
  • 3²h=90
  • 9h=90
  • h=90/9
  • h=10

hope it helps.

8 0
3 years ago
A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of p
Katena32 [7]

Answer:

Number of plain cookie boxes sold = 785 boxes

Step-by-step explanation:

Given: Cost of a chocolate chip cookie box = $1.25

Cost of a plain cookie box = $0.75

Total number of boxes sold = 1585

Total cost of the sold boxes = $1588.75

Let, number of plain cookie boxes sold = x

Number of chocolate chip cookie boxes sold = 1585 - x

So,

Total cost = total cost of the sold plain cookie boxes + total cost of the sold chocolate chip cookie boxes

$1588.75 = x ($0.75) + (1585 - x) ($1.25)

1588.75 = 0.75 x + 1981.25 - 1.25 x

0.5 x = 392.5

Therefore,

<u>Number of plain cookie boxes sold: x = 392.5 ÷ 0.5 = 785 boxes</u>

3 0
3 years ago
Read 2 more answers
9th grade math should be ez I’m tired please fast
ivanzaharov [21]

Answer:

Z=BY+R

Step-by-step explanation:

B=z-r/y

separate Z by it's self. Z= B * Y

Z =BY+R

Simple easy stuff should have no problems. I would love some more math like this bring it. C:

7 0
3 years ago
compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
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