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3 years ago

Solve the smetaneous equatan graphically x-2y=1 2x-y=2 given the range of x from-3 to 3 choose a suitable scale

Mathematics

2 answers:

DedPeter [7]3 years ago

8 0

Answer:

(2, 0)

Step-by-step explanation:

Given system:

x - 2y = 1
2x - y = 2

In order to solve it graphically, graph both lines and find the point of their intersection.

Graphing easy if you plot the x- and y- intercepts and connect them with a line.

See attached.

Both lines have same x-intercept, which is also the solution: (2, 0)

SVETLANKA909090 [29]3 years ago

4 0

x-2y=1--(1)
2x-y=2--(2)

Graph Attached

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3 years ago

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kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
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Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago

Solve the smetaneous equatan graphically x-2y=1 2x-y=2 given the range of x from-3 to 3 choose a suitable scale​

Solve the smetaneous equatan graphically x-2y=1 2x-y=2 given the range of x from-3 to 3 choose a suitable scale