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Lisa [10]
3 years ago
13

There are 20 students in a drama class. The mean age of 12 students is 18 years. The mean age of the remaining 8 students of the

drama class is 23 years. What is the mean age of all the students in the drama class?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0

Answer:

Step-by-step explanation:

Total sum of age of 12 students = 12*18 = 216;

Total sum of age of 8 students = 8*23 = 184;

Total sum of age of 20 students = 216+184 = 400;

Mean age of all the students = total age / number of students;

= 400/20 = 20 year

Step-by-step explanation:

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13x+8y+ 3z=164<br> 11x+4y+8z=144<br> 6x+2y+9z=96
Vlad [161]

Answer:

[8, 6, 4]

Step-by-step explanation:

The work is shown above, solving by using the Elimination Method.

I am joyous to assist you anytime.

8 0
3 years ago
Standar error A police officer would like to estimate the proportion of petty theft cases that have gone unsolved in a large cit
V125BC [204]

Answer:

0.625± 1.645*0.0571

Step-by-step explanation:

First calculate the estimate as 72 petty cases and 45 are unsolved as follows :

estimate :72/45=0.625

the critical value is given by cumulative probability equal to the  p* (critical probability) as ,

1)compute value for alpha =1-(confidence value /100).

                                           =1-(90/100)=0.1

for critical probability as p*=1 - (alpha/2)=1 -(0.1/2)=0.95

for this critical value is denoted to central area ,

Z(alpha)=1.645

now the standard error :

s=\sqrt{\frac{p*q}{n} }    here p is estimate and q is probability of failure and n is total no of          cases                  

 s=\sqrt{\frac{0.625*375}{72} }  =0.0571.

8 0
4 years ago
Please help me solve number 31
erica [24]
Look here the highest graph are of week3 and week 4 so the answer will be option C
4 0
3 years ago
The useful life of a certain piece of equipment is determined by the following formula: u =(8d)/h^2, where u is the useful life
Anastaziya [24]

Answer:

E. 800%

Step-by-step explanation:

Since,

u = 8d/h²      __________ eqn (1)

Now, density (d) is doubled and usage (h) is halved.

Hence the new life (u'), becomes:

u' = 8(2d)/(0.5h)²

u' = 8(8d/h²)

using eqn (1), we get:

u' = 8u

In percentage,

u' = 800% of u

In words, the percentage increase in useful life of the equipment is <u>800%</u>.

3 0
4 years ago
Read 2 more answers
Help Please I dont even know what to do :(
bazaltina [42]

Answer:

(a). Function 1

(b) Function 2

(c) Function 1,2 and 4

Step-by-step explanation:

Find the equation for all functions;

function 1: y= 2x+1

function 2: y= -2x+3

function 3: y= 5x-2

function 4: y= -4x-4

for answer of (a) y= mx+c

c is intercept. so function 1 has closest intercept to 0

for (b) the greatest y intercept is function 2

for(c) slope is m: we have function 1, 2 and 4

3 0
3 years ago
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