9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
Answer:
3 is the correct answer
u can find common ratio by dividing a specific term in GP by its preceding term. ...just as here
4/(4/3) = 3
also 12/4 = 3
also 36 /12 = 3
hence the common ratio for this GP is 3
hope it helped
Step-by-step explanation:
8500 x 6.5 x 10 + 8500 =
8500 x 6.5 + 8500 =
8500 x 6.5/100 + 8500 =
8500 x 13/20 + 8500 =
110500/20 + 8500 =
5525 + 8500 =
14025
Answer:
32/166=9/29 if two ratio are equivalent to other