times more stars are there in universe compared to human eye can see
<h3><u>
Solution:</u></h3>
Given that, conservative estimate of the number of stars in the universe is 
The average human can see about 3,000 stars at night with only their eyes
To find: Number of times more stars are there in the universe, compared to the stars a human can see
Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see
Then from given statement,
<em><u>Substituting given values we get,</u></em>
Thus times more stars are there in universe compared to human eye can see
Answer:
The possible lengths of the third side is all real numbers greater than 4 inches and less than 20 inches
Step-by-step explanation:
we know that
<u>The Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side
Let
x -----> the possible lengths of the third side
Applying the Inequality Theorem
1) 12+8 > x
20 > x
Rewrite
x < 20 in
2) 8+x > 12
x> 12-8
x > 4 in
therefore
4 in < x < 20 in
The possible lengths of the third side is all real numbers greater than 4 inches and less than 20 inches
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
This is how you write 5.24 in expanded form 5+0.2+0.04
The answer to your question is B.7/16.
The explanation for this is that 3/8 is in 16ths, 6/16, and 7/16 is greater than 6/16!
Hope this helps, if not, comment below please!!!
