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Artist 52 [7]
3 years ago
13

Using the following image, solve for x.

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:

please provide an image.

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Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
Find the value of x.
Ronch [10]

Answer:

65

Step-by-step explanation:

65+50=115

180-115=65

4 0
3 years ago
Solve the formula ..........
Flauer [41]
D=rt for t
÷r both sides
d/r=t
A
3 0
3 years ago
Is a || b? Explain using angle measurements. Your response should contain at least 3 full sentences describing how you determine
aliya0001 [1]

9514 1404 393

Answer:

  no

Step-by-step explanation:

Angles 6 and 9 are alternate interior angles where transversal 'a' crosses parallel lines p and q. As such, they are congruent. This means the measure of angle 6 is the same as that of angle 9, 110°.

Angles 6 and 8 are <em>corresponding</em> angles. If lines 'a' and 'b' were parallel, those angles would be congruent. We know angle 6 has a measure of 110° and angle 8 has a measure of 70°, so the angles are not congruent. Hence, lines 'a' and 'b' are not parallel.

__

<em>Alternate solutions</em>

Since you are not allowed to plagiarize my answer, you may be interested in other ways to show the same thing. The basic idea is to use angle relationships where transversals cross parallel lines. Ones that can be useful here are ...

  • corresponding angles are congruent
  • vertical angles are congruent*
  • alternate interior (or exterior) angles are congruent
  • sequential interior (or exterior) angles are supplementary.
  • angles of a linear pair are supplementary*

The relations marked with an asterisk (*) apply where <em>any</em> lines cross, and have no specific relationship to parallel lines. The remaining relationships only occur if the lines are parallel. Showing one of those is not true will show that the lines are not parallel.

8 0
3 years ago
Do u know it yet ????????????????
vlada-n [284]

do you know the way????????????????

8 0
2 years ago
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