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anastassius [24]
4 years ago
13

Write a quadratic variation equation if g(x) varies directly with x2, and g(x) = 108 when x = 6.

Mathematics
1 answer:
dlinn [17]4 years ago
5 0
G(x) = k * x^2

108 = k * 6^2
108 = k * 36
Divide both sides by 36
3 = k

g(x) = 3x^2
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Write an equation of the line passing through the points (4.15) and (-1. - 15).
jolli1 [7]

Answer:

y = 6x - 9

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, 15)

Point (-1, -15)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-15-15}{-1-4}
  2. Subtract:                       m=\frac{-30}{-5}
  3. Divide:                          m=6

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 6x + b
  2. Substitute:              -15 = 6(-1) + b
  3. Multiply:                  -15 = -6 + b
  4. Isolate <em>b</em>:                 -9 = b
  5. Rewrite:                   b = -9

<u>Step 4: Write linear equation</u>

<em>Substitute in all variables.</em>

y = 6x - 9

And we have our answer!

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Answer:

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Step-by-step explanation:

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Simplify 15 -3 to 12

-6x=12

divide both sides by -6

x= -12/6

Simplify 12/6 to 2

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Step-by-step explanation:

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