<h2>Answer:
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>
<h3 /><h3>Step-by-step explanation:
</h3>
<u>Find the slope of the parallel line</u>
When two lines are parallel, they have the same slope.
⇒ if the slope of this line = - 8
then the slope of the parallel line (m) = - 8
<u>Determine the equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - 11 = - 8 (x - (-1))
∴ y - 11 = - 8 (x + 1)
We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:
since y - 11 = - 8 (x + 1)
y = - 8 x + 3
The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).
You can approximate the square root of 30 by taking the square root of a number close to it. This is called local linearization. You can take the square root of 36, which is 6, and the square root of 25, which is 5, and state that the square root of 30 is approximately somewhere between 5 and 6
<span>6+5w-9f-3
Substitute the variables for numbers
6+5(3)-9(4)-3
Multiply 5 by 3 and -9 by 4
6+15-36-3
Combine like terms
Final Answer: -18
</span>
X/7-4=-2 u add two to both sides
x/7-2=0you add two to both sides again
x=14 u multiplied 7 and 2 and by x
The answer is y=3/2x+3
to figure it out:
1. you need to first find the slope of the two points.
3-0/0-(-2)
2. then put them into slope intercept form: y=mx+b. m being your slope and b being your y-intercept.
