It is given to us that the velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented by the table (which is not given to us). The acceleration due to gravity is the constant of variation. Now, we know, from basic physics that the value of the acceleration due to gravity in the SI unit is 9.8 m/s^2. Therefore, the second option is the correct option. 
Answer:
f(x)=750-15t
Step-by-step explanation:
He starts off at 750 meters, and he decends 15 meters psr minute
Answer:
-6, -4
Step-by-step explanation:
Answer:
87°10''
Step-by-step explanation:
In 49°32'55'', we convert 32' to degrees. So. 32/60 = 8/15. We also convert 55'' to degrees. So, 55 × 1/60 × 1/60 = 55/3600 = 11/720
In 37°27'15'', we convert 27' to degrees. So. 27/60 = 9/20. We also convert 15'' to degrees. So, 15 × 1/60 × 1/60 = 15/3600 = 1/240
We now add the fractional parts plus the whole part of the angles together.
So,
49 + 8/15 + 11/720 + 37 + 9/20 + 1/240 = 49 + 37 + 8/15 + 9/20 + 11/720 + 1/240 = 86 + 59/60 + 7/360.
We now convert the fractional parts 59/60 to minutes by multiplying by 60 and convert 7/360 to seconds by multiplying by 3600
86° + 59/60 × 60 + 7/360 × 3600 = 86° + 59' + 7 × 10 =86° + 59' + 70'' = 86 + 59' + 1' + 10''= 86 + 60' + 10'' = 86 + 1° + 10'' = 87° 10''
So, 49°32'55'' + 37°27'15'' = 87°10''
The correct answer is: [B]: "Difference of Cubes".
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Explanation:
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Note that the equation/identity for the "difference of cubes" is expressed as:
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" a</span>³ − b³ = (a − b)(a² + ab + b²) " ;
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Note the given equation: " 19 = 27 </span>− 8 " ; → (which is true).
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The "right hand side" of this equation:
→ " 27 − 8 " ; contains two numbers:
→ "27" and "8" ; both of which are "cubes" ;
→ that is: ∛27 = 3 ; ↔ 3³ = 3 * 3 * 3 = 9 * 3 = 27 ; <u><em>and</em></u>:
∛ 8 = 2 ; ↔ 2³ = 2 * 2 * 2 = 4 * 2 = 8 ;
→ <u>AND:</u> "8" is being <u>SUBTRACTED</u> from "27" ;
→ (hence, the "difference of squares" polynomial identity);
So: given: " 19 = 27 − 8 " ;
→ Rewrite as:
" 19 = 3³ − 2³ " ;
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Now, consider the identity equation for the "difference of squares":
→ " a³ − b³ = (a − b)(a² + ab + b²) " ;
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Take: " 19 = 3³ − 2³ " ;
and rewrite as:
→ 3³ − 2³ = 19 ;
So: (a³ − b³) = 3³ − 2³ ;
a = 3 ; b = 2 ;
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Plug in these values:
" a³ − b³ = (a − b)(a² + ab + b²) " ;
→ 3³ − 2³ ≟ [3 − 2) [ 3² + (3*2) + 2² ] ≟ 19 ? ;
→ 27 − 8 ≟ (1) (9 + 6 + 4) ≟ 19 ? ;
→ 19 ≟ (1) (15 + 4) ≟ 19 ? ;
→ 19 ≟ (1) (19) ≟ 19 ? ;
→ 19 ≟ 19 ≟ 19 ? ;
→ 19 = 19 = 19 ! Yes!
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