Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...
... 30-60-90: 1 : √3 : 2
... 45-45-90: 1 : 1 : √2
The long side of ΔMDX is 10√3, so the other two sides are
... MX = MD(√3/2) = 15
... DX = MD(1/2) = 5√3
The short side of ΔMNX is MX = 15, so the other two sides are
... NX = MX(1) = 15
... MN = MX(√2) = 15√2
Then the perimeter of ΔDMN is ...
... P = DM + MN + NX + XD
... P = 10√3 +15√2 + 15 + 5√3
... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN
11x+2=68
-2 -2
11x=66
/11 /11
X=6
Answer:
π
2
,
3
⋅
π
2
,
3
⋅
π
4
,
7
⋅
π
4
Explanation:
Factorizing your equation we get
cot
(
x
)
=
0
so
cos
(
x
)
=
0
we get the following Solutions in the given interval
x
=
π
72
or
x
=
3
π
2
for the second case we get
cot
(
x
)
=
−
1
so
cos
(
x
)
=
−
sin
(
x
)
and we get
x
=
3
π
4
or
x
=
7
π
4
Hint:
To get the Solutions of the last equation you can use
√
sin
(
x
+
π
4
)
=
0
Step-by-step explanation:
Answer:
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Answer:
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