now, let's recall the rational root test, check your textbook on it.
so p = 18 and q = 1
so all possible roots will come from the factors of ±p/q
now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.
recall that, a root will give us a remainder of 0.
let us use +3.
![\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)](https://tex.z-dn.net/?f=%5Cbf%20x%5E4-7x%5E3%2B13x%5E2%2B3x-18%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Br%7Crrrrr%7D%203%261%26-7%2613%263%2618%5C%5C%20%26%263%26-12%263%2618%5C%5C%20%5Ccline%7B1-6%7D%20%261%26-4%261%266%260%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%28x-3%29%28x%5E3-4x%5E2%2Bx%2B6%29)
well, that one worked... now, using the rational root test, our p = 6, q = 1.
so the factors from ±p/q are ±3, ±2, ±1
let's use 3 again
and of course, we can factor x²-x-2 to (x-2)(x+1).
(x-3)(x-3)(x-2)(x+1).
Answer:
"The quotient of the opposite of a number squared and 3"
Take "the opposite of a number squared" and call it y.
So you get "The quotient of y and 3"
This is y/3.
Now what is y? "The opposite of a number squared"
Take "The opposite of a number" and call it z.
So y is "z squared"
Replacing y, we get z^2 / 3
But what is z? "The opposite of a number"
Call "a number" x.
The opposite of x is -x.
So z is "-x"
Replacing z, we get (-x)^2 / 3
Answer:
Slope = 5
Step-by-step explanation:
y = mx + b
m = slope
m = 5
C. (3x+1)(3x-2) 3x times 3x= 9x^2 and 3x times -1= -3x
2 times 3x= 6x and 2 times -1= -2
9x^2- 3x+6x-2
9x^2+3x-2
Hope I explain this more clearly for you.
