1. You plug in 2 1/6 for h so it would be 3 5/6= 1 2/3+ 2 1/6
You put the mixed numbers into improper fractions
3 5/6- 23/6- 3.8
1 2/3- 5/3- 1.6
2 1/6- 13/6- 2.1
Now the equation is>> 3.8=1.6+2.1
That should help you set it up to solve. Don't let the bigger numbers scare you, break them down :)
Answer:
525
Step-by-step explanation:
This is a question involving combinatorics
The number of ways of choosing a subset k from a set of n elements is given by which evaluates to
n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1
For example,
4! = 4 x 3 x 2 x 1 = 24
3! = 3 x 2 x 1 = 6
Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is
Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1 is nothing but 4!
So the numerator can be re-written as 6 x 5 x (4!)
We can rewrite the expression
Cancelling 4! from both numerator and denominator gives us the result
as (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys
For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by
This works out to (7 x 6 x 5 )/(3 x 2 x 1) (using the same logic as for the boys computation)
= 210/6 = 35
So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525
L = length w = width
Write System of Equations:
l = 2w
l + w = 66
Substitute 2w for l:
2w + w = 66
3w = 66
w = 22
Solve for l:
l = 2w
l = 2(22)
l = ww
Answer:
y=1 1/2 (fraction)
or
y=1.5 (decimal)
Step-by-step explanation:
We want to get y alone, so we need to get rid of the 1/2 in front of it. To do that we can multiply each side by 2 since 1/2 + 1/2 = 1.
3/4= 1/2y
multiply each side by 2
To multiply 3/4 by 2 you need to multiply the numerators and then multiply the denominators
2•3=6 & 4 • 1 =4
6/4
simplify
y=1 1/2
(If you need it in decimal form it would be y=1.5)
Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!