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lianna [129]
2 years ago
11

Polygon JKLM is dilated by a scale factor of 2.5 with point C as the center of dilation, resulting in the image J′K′L′M′. If poi

nt C lies on LM¯¯¯¯¯ and the slope of LM¯¯¯¯¯ is 1.75, what can be said about L'M'¯¯¯¯¯¯¯ ?
Mathematics
1 answer:
user100 [1]2 years ago
5 0
I think the slope of L'M' is still 1.75 and it still passes through point C.
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Which of the following can be classified as Discrete and Quantitative data. The number of students in your school. The different
WITCHER [35]

Answer:

a) The number of students in your school.      

Step-by-step explanation:

Quantitative and Qualitative:

  • The data that can be expressed with the help of numerical are know as quantitative variable.
  • Qualitative variable is the non parametric variable and numerical does not describe the data

Discrete and Continuous data:

  • Discrete data are expressed in whole number and cannot take all the values within an interval.
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a) The number of students in your school.

Since whole numbers are used to express number of children it is a discrete and continuous data.

b) The different colors of the eyes of your classmates.

These are qualitative data and numerical are not used to express them.

c) The height of all the people in your neighborhood.

These are continuous data as height is measured and can be expressed in decimals.

d) The acceleration of your car as you drive to school.

These are continuous data as acceleration is measured and can be expressed in decimals.

3 0
3 years ago
Dolores and four friends went to a buffet dinner. The total costs was at most 130 dollars including the 20 dollar tip. How much
lyudmila [28]
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6 0
3 years ago
31 divided into 458
tangare [24]

Answer:

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Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
2.48030477 rounded to the nearest hundred-thousandth is
ValentinkaMS [17]
<span>2.48030, its rounded tenths 2.5  hundreths 2.48 thousands 2.480 ten-thousands 2.4803 then </span>hundred-thousandth 2.48030
3 0
3 years ago
A ball is rolled at a velocity of 12m/sec.after 36 seconds,it comes to a stop what is the acceleration of the ball?
miv72 [106K]

acceleration of ball is \frac{-1}{3}\,\,m/sec^2

Step-by-step explanation:

Initial Velocity = 12m/sec

time = 36 s

Final Velocity 0 m/sec (ball comes to stop)

Acceleration= ?

The formula used to find acceleration is:

Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}

Putting values and finding acceleration:

Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}

Acceleration=\frac{0-12}{36}

Acceleration=\frac{-12}{36}

Acceleration=\frac{-1}{3}\,\,m/sec^2

So, acceleration of ball is \frac{-1}{3}\,\,m/sec^2

Keywords: Acceleration

Learn more about Acceleration at:

  • brainly.com/question/5424148
  • brainly.com/question/10764770

#learnwithBrainly

8 0
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