The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.
|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees
= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)
= 593 in^2 + 126 in ^2 approximately
= 719 in^2 approximately
Then the length of side AC is approx. √(716 in^2) = 27 in
Answer:
x = - 19
Step-by-step explanation:
Given
x + 19 = 0 ( subtract 19 from both sides )
x = - 19
Answer:
0.00069104 approximately.
Step-by-step explanation:
You must first calculate the probability of not taking a ball with the letter B.
It would be the sum of the probabilities of taking I, N, G and O.
The probability of getting the letter I would be 15/75, that is 1/5. The same would be for the letter N, G and O. Since the 4 probabilities are equal.
Therefore it would remain (1/5) * 4 = 4/5.
Then the probability of not drawing a letter B would be 4/5.
However, in the case that it does not go out for 26 balls and that the ball that was taken out is not taken into account. It would be the multiplication of all events, that is:
(60/75) * (59/74) * (58/73) * (57/72) * ... * (35/50)
The result would be 0.00069104 approximately.
-1.4-6=-7.4
4.12+7.4=11.52
4.8n=11.52
11.52 ÷ 4.8n=2.4
n=2.4
I DONT SEE A PHOTO YOU MIGHT NEED TO ASNN ON AGAIN
