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NemiM [27]
2 years ago
15

Daniel and Alice each earn money by babysitting. Daniel earned a total of $84 in a 5-week period. During a 6-week period, Alice

averaged $16 per week. How much will Daniel have to earn in the sixth week to have the same average weekly earnings as Alice?
Mathematics
1 answer:
sweet [91]2 years ago
4 0

Answer:12

Step-by-step explanation:

16 • 6= 96

96-84=12

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yuradex [85]

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1 year ago
John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
1. A person runs 2 1/4 miles<br> in 1/2 hour. What is the<br> miles per hour?
nataly862011 [7]
4.5 mph (aka 4 and 1/2 mph)
7 0
3 years ago
these spam accounts are really about to take over this app. no fr, like, i see them on almost all of my posts as well as in the
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Answer:

Your blocking people that need help

Step-by-step explanation:

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2 years ago
Terry wants to divide his 120 baseball cards into two groups, so that the ratio of the number of cards in the first group to the
Naddik [55]
Let the number of cards in each group be 2x and 3x.
So,
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7 0
3 years ago
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