I think you mean to say "hypotenuse". If so, then use the pythagorean theorem to get the following
a^2 + b^2 = c^2
16^2 + 20^2 = c^2
256 + 400 = c^2
656 = c^2
c^2 = 656
c = sqrt(656)
c = sqrt(16*41)
c = sqrt(16)*sqrt(41)
c = 4*sqrt(41)
The hypotenuse is exactly 4*sqrt(41) units long
This is approximately 25.612 when you use your calculator.
2|x-2|-12=0
Rearrange variables to the left side of the question
2|x-2|=12
Dividing both sides of the equation by the coefficent of variables
|x-2|=12/2
Reduce the fraction
|x-2|=6
Split into two variables
x-2=6 or x-2=-6
Rearrange variables to the left side of the equation
x=6+2
x=8 or x=-4
when x=8
LHS=2|8-2|-12=0
RHS=0
LHS=RHS
x=8 is valid
A variable in mathematics is an alphabet or phrase that stands in for an unknowable amount, unknowable value, or unknowable number. Particularly in the case of algebraic expressions or algebra, the variables are utilised. As an illustration, the linear equation x+9=4 has the variables x and 9 as constants.
A variable is a letter or symbol that stands in for any individual integer in a group of two or more. A constant is a letter or symbol that stands for a single particular number, whether it is known or unknown.
In mathematics, variables serve as stand-ins for unknowable numbers. Variables can be utilized in formulae, equations, and expressions in mathematics. When it's necessary to find the optimum solution, variables are frequently employed.
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Multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
<h3>How to expand quadratic equations?</h3>
We want to expand the quadratic equation given as;
(x + 2)(4x - 3)
Multiplying out gives us;
4x² + 8x - 3x - 6
⇒ 4x² + 5x - 6
Thus, we can conclude that multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
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All percents are not whole. And no whole number can be rational, because a ration is a piece of, not a whole. I hope this helped!