1. An ice cream shop has 25 different flavors of ice cream. For each of the following, indicate whether it is a problem
1 answer:
Answer:
Step-by-step explanation:
Given that an ice cream shop has 25 different flavors of ice cream.
a) the number of different 3-scoop ice cream cones that are possible if all three scoops are different
=25P3 (since order matters as shapes or colours would be different so different order will give different type)
= 13800
b) the number of different 3-scoop ice cream cones that are possible if all three scoops are different
=25C3 (since order does not matter here)
=2300
c) the number of different ice cream cones if all three scoops could be the same, and the order of the
flavors is important
= when all three sceeps couldbe the same we can say that these are with replacement. Neither permutation nor combination
Each scoop can be any one of the 25
no of ways
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Mario says that the expression has four terms: 4, 3, n, and 2. Mario is incorrect
<em><u>Solution:</u></em>
Given that the expression is:
Given that, Mario says that the above expression has four terms
But Mraio is incorrect
Because the given expression has two terms only
4 is one of the term
is another term
So there are totally 2 terms only
A term can be a signed number, a variable, or a constant multiplied by a variable or variables
Here 3 is a constant multiplied by
So, is one term
Each term in an algebraic expression is separated by a + sign or - sign
Thus there are two terms in mario expression
Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:
0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394