I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
Answer:
i dont no but what i got was 10x+144d^3 but do u want to sovle for x i got u X
Step-by-step explanation:
Answer:
im gonna say 4 if im wrong its my fault
Answer:
(1) D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.
Step-by-step explanation:
1)
From the given figure it is noticed that


According to SAS postulate, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.
The included angles of congruent sides are angle C and angle G.
So, condition "Angle C is congruent to to Angle F" will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.
2)
If 
According to SSS postulate, if all three sides in one triangle are congruent to the corresponding sides in the other.
Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.
3)
Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.

Therefore angle C and angle F cannot be congruent to each other.
Answer:
The value of x = 2
Step-by-step explanation:
Given the equation

- Expand 12(x-2) = 12x - 24
- Expand 1/2(x+6) = 1/2x + 3
so the equation becomes

simplifying


multiplying both sides by 2

subtracting x from both sides


divide both sides by 29

simplifying

Therefore, the value of x = 2