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2 years ago

11

16/44 as its simplest form

1 answer:

lozanna [386]2 years ago

6 0

If you mean by simplifing it then it must be 4/11

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2/4 is what pieces of a whole

rewona [7]

2/4 is half of a whole

8 0

3 years ago

Read 2 more answers

What is 1 and 1/4% of 200?

arsen [322]

5/4 • 200/1, 1000/4
which is 250

250 is 1 1/4 of 200

4 0

2 years ago

Which is the prime factorization of 40?

Lana71 [14]

Hey there!

Which is the prime factorization of 40?

Option A.

2 * 5

= 2 + 2 + 2 + 2 + 2

= 4 + 4 + 2

= 8 + 2

= 10

Option B.

2^3 * 5

= 2 * 2 * 2 * 5

= 4 * 2 * 5

= 8 * 5

= 40

Option C.

2 * 53

= 53 * 2

= 53 + 53

= 106

2 * 3 * 5

= 6 * 5

= 6 + 6 + 6 + 6 + 6

= 12 + 12 + 6

= 24 + 6

= 30

Therefore, your answer is:

Option B. 2^3 * 5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

4 0

2 years ago

In a shipment of new books for a library 3/12 of the books were poetry and 2/5 of the books were biographies . The remainder of

Pepsi [2]

Answer:

Step-by-step explanation:

2/5x3/12=6/36

6 0

2 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago