For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.

Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype $X^GX^g$ . A normal man will have the genotype $X^GY$ . When the 2 marries:

$X^GX^g$ x $X^GY$ = $X^GX^G (normal female), X^GY (normal male), X^GX^g (carrier female), X^gY (affected male)$ It thus means that 50% or 1/2 of their sons will be expected to have G6PD.

Now, assuming the husband has G6PD, the mating becomes:

$X^GX^g$ x $X^gY$ = $X^GX^g (carrier female), X^GY (normal male), X^gX^g (affected female), X^gY (affected male)$ 50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.

3 0

3 years ago

Describe how rock that is exposed to the elements: air, water, changing temperatures, certain

antoniya [11.8K]

Answer:

because its energy reflects its changing

Explanation:

5 0

3 years ago