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Ipatiy [6.2K]
3 years ago
6

A bag contains 3 blue marbles and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble,

without replacing the first marble?
Mathematics
2 answers:
marin [14]3 years ago
6 0

50% because when you take out the first marble witch is probably blue since there are more blue you would have 2 blue and 2 green so the chance would be 50%

Triss [41]3 years ago
6 0

Hello!

First of all, we have the probability of getting a blue marble, 3/5. If we were to get one, we would only have 4 left. Therefore we would have 2/4, or 1/2 chance of selecting a green marble.

We multiply our probabilities.

3/4(1/2)=3/8

Therefore, there is a 3/8 or about a 36% chance.

I hope this helps!

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If line q bisects EG at point T, and if ET= 1/3 x and TG= x-2, then find EG
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