The bridge attached is drawn according to given dimensions, and it doesn't look right. Please double check the given dimensions.
Calculations:
Horizontal part of bottom chord below the 70 degree triangle
= 15.1*cos(70) = 5.16 (which is a major prt of the 6.3 units.
Height of vertical pieces DF and EH
= 15.1*sin(70) = 14.19
Note that structurally, DF and EH do not help in reducing stress on the bridge, since they are perpendicular to the bottom chord.
Therefore
angle B = atan(14.19/(6.3-5.16))=85.41 degrees
I believe the whole geometry does not look right, esthetically, and structurally, since the compression members are much longer than the tension members in the middle. (The vertical members carry no force.)
If you can review the input data, or post a new question, I will be glad to help.
When I did the math I came up as 3.88 but if you have to round up it wound be 4 or 3.9
Answer: (0,-4)
explanation: write in vertex form and use this form to find the vertex ( h , k )
Answer:
Step-by-step explanation:
If we assume that the angle at A is 90 degrees.. which it does seem like it would be. then use that the sum of the angles around the inside of a right triagle is 180 . so you have
180 = 37 + 90 + x
53° = x
does that help?