Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
This is quite easy, but anyway:
In order, they are
3, 4, 4, 5, 5, 5, 5, 7, 7
7 - 3 = 4
4 would be the range
The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have: L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides: P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2)) P = 8 * (π ^ (1/2))
