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3 years ago

D=?g/mL v=950mL m=95g

Mathematics

1 answer:

Ghella [55]3 years ago

5 0

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The graph of a function is f(x)=3√x.

suter [353]

Answer:

F(0.75)= 3/2 sq. root 3

F(9)= 9

F(7)= 3 sq. root 7

b) x= +-1

x=+-4

x= +- 49/9

3 0

2 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago

What is the lcm of 4 and 5

timama [110]

Answer:

Step-by-step explanation:

4 * 1 = 4 5 * 1 = 5

4 * 2 = 8 5 * 2 = 10

4* 3 = 12 5 * 3 = 15

4 * 4 = 16 5 * 4 = 20

4 * 5 = 20

they both go into 20 equally. there is no number lower than 20 that they both go into

8 0

3 years ago

How do you simplify this and write as a polynomial in standar form? (x-9)3x-7)+(3x^2-5x+2)

nasty-shy [4]

Answer:

Standard form of $(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=6x^{2} - 39x + 65$

Step-by-step explanation:

Here, the given expression is $(x-9)(3x-7) + (3x^{2} - 5x+2)$

Now, simplifying the above expression in parts, we get

$(x-9)(3x-7) = 3x^{2} - 7x -27x + 63 = 3x^{2} - 34x + 63$

hence, combining both parts:

$(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=(3x^{2} -34x +63) + (3x^{2} - 5x+2)$

= $6x^{2} - 39x + 65$

The above expression is of the STANDARD FORM: $ax^{2} +bx + c$

Hence, the standard form of $(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=6x^{2} - 39x + 65$

6 0

3 years ago

Help me pleaseeee thank you sm

Leno4ka [110]

Answer:

The answer is A) 379.9

Step-by-step explanation:

3.14(11^2)

3.14*11^2

3.14*(11*11)

379.94 if rounded to the nearest tenth it would be 379.9

7 0

3 years ago