∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2
∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
∠ DBC = 3x+6 = 3*13+6 = 45
∠ ABD and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2
The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs
</span>
Answer:
Could we get the question please?
Step-by-step explanation:
Answer:
<u>-1 and -5</u>
Step-by-step explanation:
m^2 + 6m + 5 = 0 is factored to: (m + 1)(m + 5) = 0.
The zero product property states that one of the represented parenthesis must equal zero to satisfy the right side of the equation.
(m + 1) = 0
(-1 + 1) = 0
This means that one of the values for m is -1.
(m + 5) = 0
(-5 + 5) = 0
This means that one of the values for m is -5.
<u>Moreover, the value of m by factoring is -1 and -5</u>
Answer:
Multiply the divisor by a power of 10 to make it a whole number.
Multiply the dividend by the same power of 10. Place the decimal point in the quotient.
Divide the dividend by the whole-number divisor to find the quotient.
The answer is a.
Substitute (-2,1) and (1,10) into each answer. Only a is correct because you will get -7 from both points.
