Answer:
6/25 km in 1 min; or 0.24 km/min
Step-by-step explanation:
The info about Angel is not necessary.
Jayden runs 3 laps in 5 mins
Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.
Distance = rate x time
6/5 km = rate (5 min)
We want to isolate r (rate), so divide both sides by 5 min
6/5 km ÷ 5 min = r
6/5 km (1/5 min) = r
6/25 km/min = r (notice how the units worked out correctly to km/min)
So, Jayden runs 6/25 km in 1 min.
Answer:
482 km
63.94 degrees
Step-by-step explanation:
to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.
Cosine rule states that
C = 
where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060
solving now, we have
C = 
C = ![\sqrt{250000 + 90000 - [215000 cos(60) }]](https://tex.z-dn.net/?f=%5Csqrt%7B250000%20%2B%2090000%20-%20%5B215000%20%20%20cos%2860%29%20%20%7D%5D)
C = ![\sqrt{340000 - [215000 * 0.5 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B215000%20%2A%200.5%20%20%7D%5D)
C = ![\sqrt{340000 - [107500 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B107500%20%20%7D%5D)
C =
C = 482 km
The bearing can be gotten by using the Sine Rule.
= 
sina/500 = sin60/482
482 sina = 500 sin60
sina = 
sina = 0.8983
a = sin^-1(0.8983)
a = 63.94 degrees
Answer:
3t-9 >= 0
Step-by-step explanation:
Original function f(t)= square root 3t-9
There cannot be a negative in the radicand therefore 3t-9 cannot equal a negative number.
Answer:
777.9 meters
Step-by-step explanation:
Notice that the angles of the right triangle are 40 and 50 degrees, with the 500 meter side adjacent to the 50 degree angle. Now, we can set up an equation: cos (50 degrees) = 500 / x. Use a calculator to find that the answer is 777.9.
Answer:
30
Step-by-step explanation:
