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miskamm [114]
2 years ago
15

Find the equation of a line that goes through the point LaTeX: \left(2,2\right)( 2 , 2 )and is parallel to the line LaTeX: y=4x-

2y = 4 x − 2.
Mathematics
1 answer:
bagirrra123 [75]2 years ago
7 0

Answer:

ghfhg

Step-by-step explanation:

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An advertising blimp hovers over a stadium at an altitude of 125 m. The pilot sights a tennis court at and 8° angle of depressio
tatuchka [14]

Answer:

Hence the ground distance is about 889m between stadium and Tennis court.

Step-by-step explanation:

Given:

A pilot at height of 125 m(flying the advertising blimp)

angle of depression=8 degrees.

To find :

The ground distance  stadium and tennis court.

Solution :

Using Trigonometric Function we can solve it ,

(Refer the attachment for fig)

Considering above data we get a triangle(ABC)

with point A represent pilot position and C court position and B as stadium.

The height AB=125 m

angle of depression= 8 degrees.

Using

<em>tan∅ =AB/BC</em>

tan(8)=125/BC

BC=125/tan(8)

=125/0.14054

=889.2

=889 m

Hence the ground distance is about 889m between stadium and Tennis court.

6 0
3 years ago
Simply the expression <br> 6(6+6+2v) HELP PLEASE ( I know my computer screen is dirty lol)
olya-2409 [2.1K]

Answer:

12v + 62

Step-by-step explanation:

distribute the 6 to 6, 6, and 2v.

36 + 36 + 12v=

12v + 72

8 0
3 years ago
Is the dolphin deeper than point C or point E?​
Pepsi [2]
Point E is correct answer
7 0
3 years ago
15. Before oil is added to a certain road surface material, the other ingredients are mixed. The mixture contains
mojhsa [17]

Answer:

sand = 3450 pounds

3/4 inch stones =6750 pounds

1 inch stones =4800 pounds.

Step-by-step explanation:

The mixture composition is :

45% three-quarter inch stones

32% inch stones and

sand for balance

The percent here is by mass of material used.

Weight of mixture is 15,000 pounds before oil addition.

Use the percent by weight for the two types of stones and calculate real values in pounds

Formula to apply is:

Mass percent = (mass of a material/ total mass of mixture) * 100

For 3/4 inch stones it will be:

0.45= \frac{x}{15000} *100\\\\0.45=\frac{x}{150} \\0.45*150=x\\x=6750

The 3/4 inch stones weigh 6750 pounds

The 1 inch stones will be

32/100 * 15000 =4800

The 1 inch stones weigh = 4800 pounds

Total for the two items : 4800+6750 =11550 pounds

The sand used weighs : 15000 - 11550 = 3450 pounds

8 0
3 years ago
I need help please.
Maslowich

Answer:

7-5m/m

Step-by-step explanation:

3 0
3 years ago
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