The area of the cross section of the column is 
Explanation:
Given that a building engineer analyzes a concrete column with a circular cross section.
Also, given that the circumference of the column is 
meters.
We need to determine the area of the cross section of the column.
The area of the cross section of the column can be determined using the formula,
First, we shall determine the value of the radius r.
Since, given that circumference is meters.
We have,
Thus, the radius is
Now, substituting the value in the formula , we get,
Thus, the area of the cross section of the column is
The value 257.3 denotes the range of the middle 50% of all observations in the distribution.
Q1 = 271.8 ; Q2 = 387.9 ; Q3 = 529.1
The Interquartile range is the difference between the the upper quartile and Lower quartile ;
- IQR = 529.1 - 271.8 = 257.3
The value of Q3 depict the 75th percentile of the data
The value of Q1 depicts the 25th percentile of the data
The difference between (Q3 and Q1) ; is the (75th - 25th) = middle 50th percentile of the distribution.
Since the difference between the maximum and minimum value is the range, then 257.3 is the range of the middle 50% of all observations in the distribution.
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Answer:
Step-by-step explanation:
Answer:
your answer would be D
Step-by-step explanation:I really hope you get it right <3 : )
Answer:
Step-by-step explanation:
<u>Given:</u>
- Initial amount of bacteria = 50000
- Growth rate = 2 times a day
<u>Required equation:</u>
<u>Solve for x:</u>
- 400000 = 50000*2^x
- 2^x = 400000/50000
- 2^x = 8
- 2^x = 2^3
- x = 3
After 3 days bacteria numbers will reach 400000
