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aliina [53]
4 years ago
10

Find the acceleration of an 800-kg car that has a net force of 4,000 N acting upon it.

Physics
1 answer:
kotykmax [81]4 years ago
3 0

Answer:

The acceleration of the car is 5m/s²

Explanation:

Given data

Force F= 4,000N

Mass of car m= 800kg

Acceleration a= ?

Applying the Newton's second law of motion which states that the rate of change of momentum of a body is proportional to the external force and takes place in the direction of the force

F=ma

a= F/m

a= 4000/800

a=5m/s²

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The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states action and reaction are equal and opposite. That is the force applied to an object is equal in magnitude to force experienced by the object but in opposite direction.

From the given question, when the bag exert a certain on the athlete, the athlete also exerts similar force to the bag but in opposite direction.

Thus, the complete sentence is as follows;

The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

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2 years ago
Which of the following is not an application of Doppler technology?
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The correct answer to the question above is the third option; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology. If the Doppler technology is being used in medical field, it would be for the ultrasound of the heart and blood vessels for examination.
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3 years ago
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I need help with 23 please.
Ne4ueva [31]
The answer is c.

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A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
Question 4 of 10 Which vector has an x-component with a length of 2?
barxatty [35]

Answer:

B

Explanation:

Look for the one with an   x coordinate of two .... answer B

4 0
2 years ago
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