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3 years ago

Which of the following is not an application of Doppler technology?

2 answers:

8 0

The correct answer to the question above is the third option; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology. If the Doppler technology is being used in medical field, it would be for the ultrasound of the heart and blood vessels for examination.

djverab [1.8K]3 years ago

3 0

Answer:

ultra sound imaging for liver

Explanation:

its correct

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While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83

allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

$\beta_{dB} = 10log_{10}\frac{I}{I_0}$

Where,

$\beta_{dB}$ = Sound intensity level in decibels

I = Acoustic intensity on the linear scale

$I_0 =$ Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

$10log_{10}(\frac{32I}{I_0}) = 83$

$10log(\frac{I}{I_0})+10log(32) = 83$

$10log(\frac{I}{I_0})= 83-10log(32)$

$10log(\frac{I}{I_0})= 67.948dB$

Therefore the sound intensity due to one person is 67.948dB

8 0

3 years ago

A population has a birthrate of 10/1000 , a death rate of 9/1000, an immigration rate of 3/1000, and an emigration rate of 7/100

Charra [1.4K]

Birth rate 10/1000 = +population

Death rate 9/1000 = -population

Immigration rate 3/1000 = +population

Emigration rate 7/1000 = -population

10/1000 - 9/1000 + 3/1000 - 7/1000= -3/1000

Growth rate = (-3/1000)(100%)= -0.3%

3 0

4 years ago

if a current of 0.3 ampere flows through a conductor of resistance of 11.7 ohm's,the voltage across the ends of the conductor is

Gnesinka [82]

Here,

Resistance = 11.7

Ampere = 0.3

Voltage = ?

Now,

R = V/A

11.7 = V/0.3

11.7*0.3 =V

V = 3.51

I hope it's help you...

Mark me as brainliest...

7 0

3 years ago

An automobile with a mass of 1240.00 kg has 3.99 m between

Vitek1552 [10]

Answer:

$948.15248\ N$

$5134.04751\ N$

Explanation:

$F_f$ = Force on front wheels

$F_r$ = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

$F_r=1240\times 9.81-F_f$

As the forces are conserved we have

$(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N$

On rear wheels

$F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N$

The force on each rear whees is $\dfrac{1896.30497}{2}=948.15248\ N$

Force on each front wheel is $\dfrac{10268.09503}{2}=5134.04751\ N$

8 0

3 years ago

The ΔG of a reaction would be at the minimum when... Group of answer choices the equilibrium constant is equal to 1 (i.e., the r

Blizzard [7]

Answer:

the equilibrium constant is equal to 1 (i.e., the reactant and product concentrations are always equal).

Explanation:

ΔG is a symbol related to Gibbs free energy, which is a physical quantity related to thermodynamics. ΔG refers to the difference between the change in enthalpy (and sometimes entropy) and the temperature of a chemical reaction.

Gibbs free energy is very useful for measuring the work done between the reactants in a reaction. It is calculated using the formula: ΔG = change in enthalpy - (temperature x change in entropy).

The ΔG of a reaction would have a minimum value (zero), if the equilibrium constant is equal to 1 (that is, the concentrations of the reagent and the product are always equal).

5 0

4 years ago