A velocity-time graph is shown below: (2 points)

Physics

1 answer:

BabaBlast [244]2 years ago

5 0

Answer:

2m/s²

Explanation:

V=Vstart+at
rewrite that to find a so a=(V-Vstart)/t

part A of graph

a=(20m/s–0m/s)/5s
a=4m/s²

part B of graph

a=(0m/s–0m/s)/5s
a=0m/s²

the average between the two is both answers added divided by the number of answers

(4m/s²–0m/s²)/2
4m/s²/2
2m/s²

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