All categories

3 years ago

A velocity-time graph is shown below: (2 points)

Physics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

2m/s²

Explanation:

V=Vstart+at
rewrite that to find a so a=(V-Vstart)/t

part A of graph

a=(20m/s–0m/s)/5s
a=4m/s²

part B of graph

a=(0m/s–0m/s)/5s
a=0m/s²

the average between the two is both answers added divided by the number of answers

(4m/s²–0m/s²)/2
4m/s²/2
2m/s²

You might be interested in

If a cart is accelerating downhill under a net force of 25 N, what additional force would cause the cart to have a constant velo

Vladimir [108]

No additional force is required because it's already going downhill

7 0

2 years ago

When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?

SashulF [63]

Given data

*The value of battery voltage is V = 10 V

*The current flows through the resistor is I = 5 A

The formula for the resistor is given by the Ohm's law as

$R=\frac{V}{I}$

Substitute the values in the above expression as

$\begin{gathered} R=\frac{10}{5} \\ =2\text{ ohm} \end{gathered}$

7 0

1 year ago

Conditional probability involves events that are independent. true or false?

kiruha [24]

Its false I got It right .

3 0

3 years ago

Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal

Dmitry_Shevchenko [17]

Answer:

$a = \dfrac{4\pi^2R}{T^2}$

Explanation:

The acceleration of a circular motion is given by

$a = \omega^2 R$

where $\omega$ is the angular velocity and $R$ is the radius.

Angular velocity is related to the period, T, by

$\omega=\dfrac{2\pi}{T}$

Substitute into the previous formula.

$a = (\dfrac{2\pi}{T})^2 R$

$a = \dfrac{4\pi^2R}{T^2}$

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

6 0

2 years ago

Question 1 of 10

Marianna [84]

Answer:

Option D. ²²²₉₀Th

Explanation:

Let the unknown be ⁿₘZ. Thus, the equation becomes:

²²⁶₉₂U —> ⁴₂He + ⁿₘZ

Next, we shall determine n, m and Z. This can be obtained as follow:

For n:

226 = 4 + n

Collect like terms

226 – 4 = n

222 = n

n = 222

For m:

92 = 2 + m

Collect like terms

92 – 2 = m

90 = m

m = 90

For Z:

ⁿₘZ => ²²²₉₀Z => ²²²₉₀Th

Therefore, the complete equation becomes:

²²⁶₉₂U —> ⁴₂He + ⁿₘZ

²²⁶₉₂U —> ⁴₂He + ²²²₉₀Th

Thus, the unknown is ²²²₉₀Th

6 0

3 years ago