Is 120% less than, more than or equal to 1

A survey revealed that 31% of people are entertained by reading books, 39% are entertained by watching TV, and 30% are entertain

tester [92]

1% entertained by books
9% entertained by TV

3 0

3 years ago

F(x)=e^(4x)+e^(4x) need the answer

brilliants [131]

Answer:

Step-by-step explanation:

F(x)=e^(4x)+e^(4x) =2e^(4x)

5 0

3 years ago

WILL MARK BRAINLIEST !!!<br> find the indicated value for each of the figures shown or described

timama [110]

Answer:

10. 9

In the first question we can solve using the Pythagorean theorem. It states that the hypotenuse in a right triangle or the longest side of the triangle, squared is equal to the other 2 sides, squared. Its expressed as so: C^2 = A^2 + b^2 where c is the hypotenuse and a and b are the other sides oft eh triangle.

Therefore,

15^2 = 12^2+x^2

225=144+x^2

81=x^2

x=9

__________________________________________________________

11. x=12

In this figure, there are 2 right triangles on the sides of the square. If we can find the lengths of the base of both triangles then we can find x using the Pythagorean theorem. the total base is 21 and the square is 11. 11+a+b=21. We can assume that both triangles are congruent and therefore we can solve this equation:

11+a+b=21

a+b=10

5+5=10

b=5

a=5

The bases of the two triangles are 5 and the hypotenuse is 13. Now we can solve using the Pythagorean theorem:

c^2 = a^2+b^2

13^2=5^2+x^2

169=25+x^2

144=x^2

144= 12 x 12

x=12

__________________________________________________________

12.

The diagnol of a triangle is the hypotenuse and since the length is the square root of 3, we have all the information we need.

c^2 = a^2+b^2

2^2 = (square root of 3)^2+b^2

4=3+b^2

1=b^2

b=1

Step-by-step explanation:

6 0

3 years ago

A study of the pricing accuracy of checkout scanners at a store found that one of every 20 items is priced incorrectly. On any g

GalinKa [24]

Answer:

a) There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) 20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) 22.62% probability that at least one of the five items is priced incorrectly by the scanner

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is priced correctly, or it is not. The probability of an item being priced incorrectly is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Five items selected.

This means that $n = 5$

One of 20 is priced incorrectly.

This means that $p = \frac{1}{20} = 0.05$

a) Assuming that this store sells thousands of items every day, which probability distribution would you use and why?

There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) What is the probability that exactly one of the five items is priced incorrectly by the scanner?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.05)^{1}.(0.95)^{4} = 0.2036$

20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) What is the probability that at least one of the five items is priced incorrectly by the scanner?

Either no items are priced incorrectly, or at least one is. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 0$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7738 = 0.2262$

22.62% probability that at least one of the five items is priced incorrectly by the scanner

5 0

3 years ago

Probability is a fraction (or ratio in fraction form) that shows the number of favorable cases to the __________ number of cases

Paladinen [302]

The answer should be A total

7 0

3 years ago

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