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3 years ago

Find the initial value of the function x + 3y = 18

Mathematics

1 answer:

brilliants [131]3 years ago

7 0

X+3y=18
x+3y-18=18-18
x+3y-18=0
x+3y-18=0 ( << that’s your answer) hope it helps

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Rom4ik [11]

Answer:10,950=350x+475y

X=trumpet

Y=trombone

Step-by-step explanation:

8 0

3 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0

3 years ago

The room measures 8 inches by 5 inches on the blueprint. If the scale on the blueprint is 1 inch by 4 feet, what is the actual a

larisa86 [58]

Hi there!

To solve this problem, we need to multiply each number by 4 ft.

8×4=32
5×4=20

Now, we films the area.

32×20 = 640

The area of the room is 640 feet squared.

Hope this helps!

3 0

3 years ago

5 friend's are having a tennis tournament.Each friend will play the other 4 friend once. How many matches will be played

Paraphin [41]

The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.

3 0

3 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

lubasha [3.4K]

Answer:

The answer is option C.

Step-by-step explanation:

The arithmetic sequence is given by

$A(n) = - 6 + (n - 1)( \frac{1}{5} )$