1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luda [366]
3 years ago
6

A blue whale calf weighed 2725 kilograms at birth. A blue whale calf gains 90 kilograms of weight each day for the first 240 day

s after its birth. What is the weight after 225 days after it’s birth
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:the weight after 225 days is

22885 kilograms

Step-by-step explanation:

The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.

The formula for the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

n is the number of terms of the sequence.

a is the first term

d is the common difference

We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225

Therefore

T225 = 2725 + (225 - 1)90

T225 = 2725 + 224×90 = 2725 + 20160

T225 = 22885

You might be interested in
Use the following area model to multiply 29x97
alexandr402 [8]
The answer to 29×97 would be 2813
6 0
3 years ago
1. Is the function below linear or non linear? y = -8X2 + 9??​
romanna [79]
Linear because it’s in y=mx+b form
3 0
3 years ago
I missed when we learned abt this in school!!! Pls someone help. I’m so clueless:(
BigorU [14]

Answer:

Graphs: 14, 16, and 17 are graphs of proportional relationships. The constants of proportionality are 3/2, -1/4, and 1, respectively.

Missing values: 18: 12; 19: 6; 20: 21; 21: -4; 22: -5; 23: 40.

Step-by-step explanation:

<em>Explanation for Graphs</em>

The graph of a proportional relation is <em>always a straight line through the origin</em>. The graph of 15) is not such a graph, so is not the graph of a proportional relation.

The constant of proportionality is the slope of the line: the ratio of vertical change to horizontal change. In each of these graphs, points are marked so it is easy to count the squares between marked points to determine the amount of change. (One of the marked points in each case is the origin.)

14) The graph goes up 3 for 2 squares to the right, so the slope and constant of proportionality are 3/2.

16) The graph goes down 1 square for 4 squares to the right, so the slope and constant of proportionality are -1/4.

17) The graph goes up 3 squares for 3 squares to the right, so the slope and constant of proportionality are 3/3 = 1.

_____

<em>Explanation for Missing Values</em>

When 3 values are given and you're asked to find the 4th in a proportion, there are several ways you can do it. Here's one that may be easy to remember, especially if you write it down for easy reference when you need it.

Let's call the given values "a", "b", and "c". They can be given in ordered pairs, such as (x, y) = (a, b) = (2, -4), and a missing value from an ordered pair, such as (c, _) = (-6, y). (These are the numbers from problem 18.)

In this arrangement, the "_" is the second value of the second ordered pair, so corresponds to "b", the second value of the first ordered pair. The value "c" is the other half of the ordered pair with a value missing, so it, too, can be said to correspond to the "_".

The solution is the product of these two corresponding values, divided by the remaining given value. That is, for ...

... (a, b) = (c, _)

the unknown value is

... _ = bc/a

___

If the relation is written with the first value missing, the same thing is true: the solution is the product of corresponding values divided by the remaining given value.

... (a, b) = (_, c)

... _ = ac/b

___

This still holds when the pairs are on the other side of the equal sign.

  • For (c, _) = (a, b), the solution is _ = bc/a
  • For (_, c) = (a, b), the solution is _ = ac/b

_____

18) y = (-6)(-4)/2 = 12

19) x = (4)(24)/16 = 6

20) y = (12)(7)/4 = 21

21) x = (-16)(6)/24 = -4

22) x = (3)(30)/-18 = -5

23) x = (32)(100)/80 = 40

_____

<em>More Formally ...</em>

In more formal terms, the proportional relation can be written as

... b/a = _/c . . . . for (a, b) = (c, _)

Multiplying both sides of this equation by c gives ...

... bc/a = c_/c

Simplifying gives

... bc/a = _

When the missing value is the other one in the ordered pair, we can still write the proportion with the missing value in the numerator, then solve by multiplying the equation by the denominator under the missing value.

... a/b = _/c . . . . for (a, b) = (_, c)

... _ = ac/b

6 0
3 years ago
Help Please Brainliest!
Vera_Pavlovna [14]
The answer is about 9.73 times as many pixels!
5 0
3 years ago
Read 2 more answers
How add with the same denominator ?
Amiraneli [1.4K]

Answer:

you just add the top numbers and then if its over the denominator you simplify

Step-by-step explanation:

7/9 + 4/9

10/9

1-1/9

7 0
3 years ago
Other questions:
  • Julianne needs 7 yards of string for her kite. She
    8·1 answer
  • The quotient of j and 8" can be expressed as:
    11·1 answer
  • A square is inscribed in a circle of radius 3 square root 2 find the area
    6·1 answer
  • Are all even numbers divisible by 4?
    13·2 answers
  • 409381886 rounded to the nearest hundred thousand
    10·2 answers
  • (25a + 9d) - (10a - 5d)​
    7·2 answers
  • On a road trip, a family drove 60 miles per hour for their entire trip. Which of the following rates could they have been drivin
    7·1 answer
  • Need help with math ​
    6·1 answer
  • Rewrite the expression using a DIVISION SYMBOL: "The quotient of m and 7."
    5·1 answer
  • Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coeffici
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!