Radius equals: 4.51
hope this helps! ♥
Answer:
okay so the first question says divide :40203 by 13
= after dividing the quotient comes as 3092
Step-by-step explanation:
then to verify the answer using division algorithm
the formula is as dividend = (q x d) + remainder
so the verification= 13 x 3092 + 7 = 4023
the second question says to find the difference between the pv of two 4's in 948475
the answer is 40000 - 400 = 39600ans.
the third question's answer will be:
amount mohan deposited in his savings Bank account= ₹35000
amount he withdrawed = ₹6245
therefore total amount of money left in his account =
₹28755ans.
Hope it helps!!!!!!!!!!
pls mark as brainliest!!!!!!
Answer:
Angle of elevation from Kim to the satellite launch = 6.654°
Step-by-step explanation:
The distance from Kim to the satellite launch
= 6 miles
Height of the satellite launch
= 0.7 miles
Angle of elevation from Kim to the satellite launch = b
Tan b = height of satellite/distance from Kim
Tan b= 0.7/6
Tan b= 0.1166667
b = tan^-1 (0.1166667)
b= 6.654°
Angle of elevation from Kim to the satellite launch = 6.654°
Answer:
b) 690 - 7.5*t
c) 0 < t < 92s time (t) is independent quantity
d) 0 < s < 690ft distance from bus stop (s) is dependent quantity
e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop
Step-by-step explanation:
Part a - see diagram
part b
initial distance from bus stop s0 = 690 ft
distance covered = 7.5*t
s = s0 - distance covered
s = 690 - 7.5*t = f(t)
part c
s = 0 or s = 690
0 = 690 -7.5*t
t = 92 s
Hence domain : 0 < t < 92s time (t) is independent quantity
part d
s = 0 or s = 690
Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)
part e
f(0) is s @t = 0
f(0) = 690 ft away from bus stop
f(60.25) is s @t = 60.25
f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.
