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juin [17]
3 years ago
11

Find the point that splits segment AB in half if point A is located at (4,3) and point B is located at

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

The point that splits the segment AB in half is C\left ( 1,4.5 \right )

Step-by-step explanation:

Given: Point A is located at \left ( 4,3 \right ) and point \left ( -2,6 \right )

To find: Point that splits segment AB in half.

Solution: Let C\left ( x_{3},y_{3} \right) be the point that splits AB in half.

We know that the mid point \left ( x_{3},y_{3} \right ) of a line segment joining the points \left ( x_{1},y_{1} \right ) and \left ( x_{2},y_{2} \right ) is calculated as \left (\frac{x_{1}+x_{2}}{2},\:\frac{y_{1}+y_{2}}{2} \right )

Here, x_{1}=4,\:x_{2}=-2,y_{1}=3,y_{2}=6

x_{3}=\frac{4-2}{2}

x_{3}=\frac{2}{2}

x_{3}=1

y_{3}=\frac{3+6}{2}

y_{3}=\frac{9}{2}

y_{3}=4.5

Hence, the point that splits the segment AB in half is C\left ( 1,4.5 \right )

musickatia [10]3 years ago
5 0

Answer:

(1, 4.5 )

Step-by-step explanation:

The required point is at the midpoint of AB

Use the midpoint formula

Given A(4, 3) and B(- 2, 6 ), then

midpoint = [ 0.5(4 - 2), 0.5(3 + 6) ] = (1, 4.5 )

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What does -3(n+5)=12 equal
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Answer:

n= -9

Step-by-step explanation:

-3 ( n+5 ) = 12

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6 0
4 years ago
Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type
Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

\frac{y}{t} = e^{-kt + C}  \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt}   (A = e^{C})\\y = Ate^{-kt}

when t = 1 hour, y = 15 grams. So,

y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}(1)

when t = 3 hours, y = 30 grams. So,

y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k} (2)

dividing (2) by (1), we have

\frac{30}{15}  = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36

Substituting A and k into y, we have

y = 18.36te^{-0.203t}

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0
3 years ago
Calculate dy/dx if Ln (x + y) = e^x/y<br> Pic included
vesna_86 [32]
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 The answer for this case is D
 I attach the solution

7 0
4 years ago
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