Answer:
The probability that a randomly selected carton has a puncture or a smashed corner is 0.143
Step-by-step explanation:
we know that P(A∪B) = P(A) + P(B) - P(A∩B).
since given that P(A) = Probability of getting puncture = 0.08
P(B) = probability of getting smashed corner = 0.07
P(A∩B) = probability of getting both puncture and smashed corner = 0.007
P(A∪B) = probability of getting any of them
so P(A∪B) = 0.08 + 0.07 -0.007 = O.143
$12 5 times 3 is 15 -20% is $12
Lawrence's is the correct answer. he put 3 plates on each box in both situations
Equal in what? Cm, m, mm ?
