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Paraphin [41]
4 years ago
13

25-28 i need help with

Mathematics
1 answer:
valina [46]4 years ago
3 0
Don't understand the question your asking
You might be interested in
A campus deli serves 300 customers over its busy lunch period from 11:30 a.m. to 1:30 p.m. A quick count of the number of custom
NeX [460]

Answer:

4 minutes

Step-by-step explanation:

There are two hours from 11:30 a.m. to 1:30 p.m

The hourly rate of service is:

r=\frac{300}{2}=150\ customers/hour

If the average number of customers in the system (n) is 10, the time that a customer spends in process is given by:

t=\frac{n}{r} =\frac{10}{150}=0.06667\ hours

Converting it to minutes:

t= 0.066667\ hours*\frac{60\ minutes}{1\ hour}\\t=4\ minutes

A customer spends, on average, 4 minutes in process.

7 0
4 years ago
Add or subtract. write in simplest form 21/9+74/9=
motikmotik
21/9 + 74/9 = (21 + 74)/9 = 95/9 = 10 5/9
5 0
3 years ago
Need help solving this problem
tigry1 [53]

Answer:

46-22= 24

Therefore, the answer is ;

A.24

3 0
3 years ago
I need help with this
Nana76 [90]

Answer: -0.5

Step-by-step explanation:

We can see that at x=0 that Y=2, when x=2, y=1, so we do the x1 - x2 = -2 and y1-y2 = 1

Then we do 1 / -2 = -0.5

The average rate of change is -0.5

3 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
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