Answer:
2/5 hour is closest to 0 1/2 hours, 5/8 hour is closest to 1/2 hour. Therefore, the best estimate for the total time Maria spent with her sister is close to 1 hour
Step-by-step explanation:
We can represent the time Maria spends playing the game as 0.4, since 2/5 as a fraction is 0.4. This is closer to 1/2, which is 0.5 then it is to 0, because 4 is closer to 5 then 0. Then, we can represent the time Maria reads the book as 0.625, which is closer to 1/2 then it is to 1. Now we can add the estimated times.
hour
Part (i)
<h3>Answer:
x^2 + 5x + 6</h3>
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Work Shown:
(x+3)(x+2)
y(x+2) ..... Let y = x+3
y*x + y*2 ... distribute
x(y) + 2(y)
x(x+3) + 2(x+3) .... plug in y = x+3
x*x + x*3 + 2*x + 2*3 ... distribute
x^2 + 3x + 2x + 6
x^2 + 5x + 6
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Part (ii)
<h3>Answer:
4x^2 - 16x + 7</h3>
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Work Shown:
We could follow the same set of steps as shown back in part (i), but I'll show a different approach. Feel free to use the method I used back in part (i) if the visual approach doesn't make sense.
The diagram below is a visual way to organize all the terms. Many textbooks refer to it as "the box method" which helps multiply out any two algebraic expressions.
Each inner cell is found by multiplying the corresponding outer terms. For instance, in the upper left corner we have 2x*2x = 4x^2. The other cells are filled out the same way.
The terms in those four inner cells (gray boxes) are:
The like terms here are -14x and -2x which combine to -16x, since -14+(-2) = -16.
We end up with the answer 4x^2-16x+7
The question is worded poorly, but it looks like you have a lever in equilibrium, with a force x at a distance d from the fulcrum, and a force y at a distance L - d from the fulcrum. You already have the equilibrium formula for this situation:
xd = y(L - d)
If you know x, y, and d, you can solve for the length L.
Answer:
no figure 1 isn't similar to figure 2
Step-by-step explanation:
because its sides aren't the same numbers nor do the numbers correlate with the numbers in figure one its 2 different numbers
Dilation about the origin multiplies every coordinate by the scale factor.
C' = 4(-5, 2) = (-20, 8)
A' = 4(-4, 4) = (-16, 16)
T' = 4(-1, 2) = (-4, 8)