Answer:
The last graph
Step-by-step explanation:
The problem presented here is similar to a compound interest problem since we have an initial value, a growth constant and the aspect of time.
We can consider the number of television sets currently produced by the company to be our Principal amount;
P = 2000
The rate of increase in production per month can be considered as our interest rate earned;
r = 25% = 0.25
The total number of television sets y will be our Accumulated amount;
A = y
The duration x becomes our time n.
The compound interest formula is given as;
We simply substitute the given information into the formula;
This is an exponential growth function since the base of the exponent x is greater than 1.
A graph of the function will be an exponential curve passing through ( 0, 2000) since 2000 is our initial value
Answer:
6c^2-cd-d^2
Step-by-step explanation:
How you get the answer is you use the process called FOIL. The F is front, so you multiply the 2c and the 3c to get 6c^2. The O is the outer, so you multiply the 2c and the d(because they are on the outer sides of the parenthesis) to get 2cd. The I is the inner, so you multiply the -d and the 3c(because they are on the inner sides of the parenthesis) to get -3cd. The L is the last, so you multiply d and -d to get -d^2. The 2cd and the -3cd are the same so you have to minus them to get -cd. So the answer is:
6c^2-cd-d^2.
The correct answer is the first one.
5 x 100 is correct.
9 x 1 is correct because the 9 is in the ones section, not the tens.
3 x 1/10 is correct because it is equal to 0.3.
7 x 1/1000 is correct because it is equal to 0.007.
Hope this helped! You’re welcome
Answer:
Thus, the value of expression is .
Step-by-step explanation:
Given : 3 + (2 + 8)power 2 ÷ 4 × 1 over 2 to the power of 4
Mathematically written as
We apply BODMAS,
Where ,
B stands for brackets
O stands for order
D stands for division
M stands for multiplication
A stand for addition
S stands for subtraction.
Consider the given expression,
Using BODMAS rule, solving for brackets first,
Thus, the value of expression is
