Answer:
Step-by-step explanation:
Xét ∆ABC có:
C= 180-30-45=105°
D= 180-105-45÷2= 75-22,5= 52,5°
Given:
One interior angle is 50°.
Exterior angle is 95°.
To find:
The value of x and y.
Solution:
Exterior angle property of triangle:
The measure of an exterior angle is equal to the sum of the measures of the opposite interior angles.
⇒ 50° + y = 95°
Subtract 50° from both sides.
⇒ 50° + y - 50° = 95° - 50°
⇒ y = 45°
Sum of the adjacent angles in the straight line is 180°.
⇒ x + 95° = 180°
Subtract 95° from both sides.
⇒ x + 95° - 95° = 180° - 95°
⇒ x = 85°
The value of x is 85° and y is 45°.
(-3,-1),(0,-2),(1,5),(4,3)
4-2(1)=
4-2=2
So basically the answer is 2
Answer:
Step-by-step explanation:
First of all let's notice that 
while our original polynomial is real. So we can rule out the even options B and D. At this point, if the polynomial has a factor of 
it means tha 
is a zero of the polynomial. Let's check both 2 (for option a) and -2 (for option c)
At this point 2 is a zero, and our final factoring is a
