Answer:
Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n 
3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have
f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n 3.
C. 5/14
You find the LCD. In this case it would be 14 since both 7 and 14 can go into 14. You have to multiply the top by the same number as the bottom. 2*7=14
2*3=6. You now have 6/14. 6-1=5
The denominator stays the same. 5/14
Answer:
![{ \tt{pH = - log[H {}^{ + } ]}} \\ pH = - log(4.2 \times {10}^{ - 5} ) \\ pH = 4.38](https://tex.z-dn.net/?f=%7B%20%5Ctt%7BpH%20%3D%20%20-%20%20log%5BH%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%7D%7D%20%5C%5C%20%20pH%20%3D%20%20-%20%20log%284.2%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%29%20%20%5C%5C%20pH%20%3D%204.38)
Step-by-step explanation:
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