Temperature and Pressure One way to increase the solubility of a gas is to decrease the temperature of the liquid. The solubility of a gas in a liquid is usually temperature dependent, although it depends on the particular combination of which gas and which liquid. Usually the solubility of a gas goes down with increasing temperature (think of warm carbonated beverages going flat).
<span>The other way to increase the solubility is to increase the pressure of the gas. The higher the pressure of the gas above the liquid, the more will dissolve. Again, think of a carbonated beverage: when it is sealed it doesn't go flat because it is under pressure, but when open to air, it will go flat. </span>
Answer:
20% of phosphorus
Explanation:
A fertilizer is used to improve the fertility of soils. Most fertilizers contains the element nitrogen, phosphorus and potassium.
They are often designated NPK fertilizers.
Now we know that the numbers 10-20-20 depicts the nitrogen-phosphorus and potassium content of the fertilizer.
From the designation,
The actual percentage is 20% of phosphorus.
10% of nitrogen
20% of potassium
Answer:
See explanation
Explanation:
Before the advent of the wave-particle duality theory proposed by Louis de Broglie, there was a sharp distinction between mater and waves.
However, Louis de Broglie introduced the idea that mater could display wave-like properties. Erwin Schrödinger developed this idea into what is now known as the wave mechanical model of the atom.
In this model, electrons are regarded as waves. We can only determine the probability of finding the electron within certain high probability regions within the atom called orbitals.
This idea has been the longest surviving atomic model and has greatly increased our understanding of atoms.
I think thee correct answer from the choices listed above is option D. <span>When a physical change in a sample occurs, composition of the sample does not change. It stays the same. Also, the properties of the sample will still be the same. Hope this answers the question.</span>
