Answer:
H2-1
H2+-1/2
H22- zero
Explanation:
Bond order= Bonding electrons-antibonding electrons/2
In H2, there are two bonding electrons and no antibonding electrons. In H2+ there is only one bonding electron and no antibonding electron while in H22- there are two bonding and two antibonding electrons respectively.
Answer:
The temperature would be 304, 87 K
Explanation:
We use the formula PV= nRT:
T= PV/nR = 1,00 atm x 100L /4,00 mol x 0,082 l atm/K mol=<em>304, 87 K</em>
Answer:
c. 29 J
Explanation:
Step 1: Given data
- Specific heat capacity of Pb (c): 0.13 J/g.K (= 0.13 J/g.°C)
- Initial temperature: 22 °C
Step 2: Calculate the temperature change
ΔT = 37 °C - 22 °C = 15 °C
Step 3: Calculate the heat (Q) required to raise the temperature of the lead piece
We will use the following expression.
Q = c × m × ΔT
Q = 0.13 J/g.°C × 15 g × 15 °C = 29 J
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