Answer:
Standard error = 0.070
Step-by-step explanation:
Formula for the standard error of the distribution of differences in sample proportions is;
σ_(A - B) = √((p_a^(1 - p_a^)/n_a) + (p_b^(1 - p_b^)/n_b))
We are given;
p_a^ = 0.48
n_a = 80
p_b^ = 0.13
n_b = 66
Thus;
σ_(A - B) = √((0.48(1 - 0.48)/80) + (0.14(1 - 0.13)/66))
σ_(A - B) = √0.00496545455
σ_(A - B) = 0.070
Answer:
x = 14.5
Step-by-step explanation:
Exterior angle thm
<C = <D
7x - 2 = 9x - 31
7x - 9x = -31 + 2
-2x = -29
x = 14.5
Let's solve the first inequality at first. So,
−2(x + 4) + 10 < x − 7
-2x- 8 + 10 < x - 7 By distribution property.
-2x + 2 < x - 7 Adding the like terms.
-2x < x - 7 - 2 Subtract 2 from each sides.
-2x < x - 9 By simplifying.
-2x - x < -9 Subtract x from each sides.
-3x < -9
Since we are dividing by negative 3. So, sign of inequality will get change.
So, x>3
Now the next inequality is,
−2x + 9 > 3(x + 8)
-2x + 9 > 3x + 24
-2x > 3x + 24 - 9
-2x > 3x + 15
-2x - 3x > 15
-5x >15

So, x <-3
Hence, the correct choice is x > 3 or x < −3.
Answer:
Equilateral triangle will always have a perpendicular bisector that is also an angle bisector.
Step-by-step explanation:
Equilateral triangle property:
- All sides of the equilateral triangle are equal.
- Angle of every equilateral triangle are equal to 60°.
- Every altitude of an equilateral triangle is also a median and a bisector.
- Each median is also an altitude and a bisector.
- Each bisector is also an altitude and a median.
Therefore, by equilateral triangle property;
Perpendicular bisectors are angle bisectors in an equilateral triangle Since, all sides and angles are the same in an equilateral triangle.
Also, the angle bisector of an equilateral triangle forms 90 degree angle with the opposite side and bisects that side.
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)