Answer:
The length of segment DC 33 units.
Step-by-step explanation:
Given:
The length of segment BC is 23 units.
To find:
Length of segment DC=?
Solution:
AB = 2x + 7
From the figure ,AB = BC
2x + 7 = 23
2x = 23 - 7
2x = 16
x = 8
In the Δ ABD and ΔCBD
(1) AB = BC(As given in the figure.)
(2) ∠DBA = ∠DBC = 90°
(3) BD = BD(Common side of both the triangle.)
Thus by using SAS congurence property .
Δ ABD ≅ ΔCBD
Thus AD = DC(Corresponding sides of the congurent triangle.)
Thus AD = 4x + 1
Substituting x = 8
AD = 
AD = 32 + 1
AD = 33 unit
Thus AD = DC = 33 unit
There are four parts of a circle, so you have to find out the area of the circle:-
10 cm=Radius
=100
=3.14
3.14*100=314 
Now, find the area of the square box:-
Since half the side of the square is 10 cm, the total length of one side is 2*10 which is 20 cm.
Area=S*S
=20*20=400 
Now subtract the area of the box from the area of the square:-
400-314= 86
That is the area of the shaded part.
Happy to help you!
EFHG => EF = AC = 3cm and EG = AB = 10cm, so the area = 3*10 = 30 cm^2
ACFE => AC = 3cm and FC = 2cm, so the area = 3*2 = 6 cm^2