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3 years ago

Need help to find all of the relationships in this

Mathematics

2 answers:

babymother [125]3 years ago

5 0

The answers are:
• A
• C
• E

just olya [345]3 years ago

5 0

Answer:

A,C,E

Step-by-step explanation:

adjacet, complementary, and linear pair

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which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x

pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case if the point $(2,80)$ satisfied the exponential function

case A $f(x)=4(x^{5})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(2^{5})=128$

$128\neq 80$

therefore

the exponential function $f(x)=4(x^{5})$ not passes through the point $(2,80)$

case B $f(x)=5(x^{4})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(2^{4})=80$

$80=80$

therefore

the exponential function $f(x)=5(x^{4})$ passes through the point $(2,80)$

case C $f(x)=4(5^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(5^{2})=100$

$100\neq 80$

therefore

the exponential function $f(x)=4(5^{x})$ not passes through the point $(2,80)$

case D $f(x)=5(4^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(4^{2})=80$

$80=80$

therefore

the exponential function $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

the answer is

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

7 0

3 years ago

AngleFBC and AngleCBG are supplements, AngleDBG and AngleDBF are supplements, and AngleCBG Is-congruent-to AngleDBF. 4 lines are

aniked [119]

Answer:

Step-by-step explanation:

i just did it on edginity

5 0

2 years ago

Which three lengths CANNOT be the lengths of the sides of a triangle? A. 23 m, 17 m, 14 m B. 11 m, 11 m, 12 m C. 5 m, 7 m, 8 m D

Mariulka [41]

D. 21cm because you divide all sides by 2 then get your slope form and multiply by seven

7 0

3 years ago

Read 2 more answers

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

Anika [276]

For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4

Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1

Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20

Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3

6 0

3 years ago

What is an equation of the line that passes through the points (3,-3) and (-3,-3)?

victus00 [196]

First find the gradient of the line
Change in y/change in x
-3–3/-3-3
0/-6
=0 ( so the gradient m is equal to zero)

Y=0x+c

Input the coordinates of one point to find c

-3=(0*3)+c
-3=c

So the equation is
Y= -3

3 0

3 years ago