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rusak2 [61]
3 years ago
15

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

Mathematics
1 answer:
Anika [276]3 years ago
6 0
For this case we have the following functions:
 h (x) = 2x - 5
 t (x) = 6x + 4

 Part A: (h + t) (x)
 (h + t) (x) = h (x) + t (x)
 (h + t) (x) = (2x - 5) + (6x + 4)
 (h + t) (x) = 8x - 1

 Part B: (h ⋅ t) (x)
 (h ⋅ t) (x) = h (x) * t (x)
 (h ⋅ t) (x) = (2x - 5) * (6x + 4)
 (h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
 (h ⋅ t) (x) = 12x ^ 2 - 22x - 20

 Part C: h [t (x)]
 h [t (x)] = 2 (6x + 4) - 5
 h [t (x)] = 12x + 8 - 5
 h [t (x)] = 12x + 3
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The recursive geometric sequence that models this situation is:

f(n) = 0.9f(n-1)

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<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

It can be represented by a recursive sequence as follows:

f(n) = qf(n-1)

With f(1) as the first term.

In this problem, the sequence is: 90.000: 81,000; 72,900; 65,610, hence:

q = \frac{65610}{72900} = \cdots = \frac{81000}{90000} = 0.9

f(1) = 90000

Hence:

f(n) = 0.9f(n-1)

f(1) = 90000

More can be learned about geometric sequences at brainly.com/question/11847927

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