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rusak2 [61]
3 years ago
15

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

Mathematics
1 answer:
Anika [276]3 years ago
6 0
For this case we have the following functions:
 h (x) = 2x - 5
 t (x) = 6x + 4

 Part A: (h + t) (x)
 (h + t) (x) = h (x) + t (x)
 (h + t) (x) = (2x - 5) + (6x + 4)
 (h + t) (x) = 8x - 1

 Part B: (h ⋅ t) (x)
 (h ⋅ t) (x) = h (x) * t (x)
 (h ⋅ t) (x) = (2x - 5) * (6x + 4)
 (h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
 (h ⋅ t) (x) = 12x ^ 2 - 22x - 20

 Part C: h [t (x)]
 h [t (x)] = 2 (6x + 4) - 5
 h [t (x)] = 12x + 8 - 5
 h [t (x)] = 12x + 3
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If 433 = 100% then what percent does 383 equal
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Answer:

88.46%

Step-by-step explanation:

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<u>Check work:</u>

433 x 88.46% = 383

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Explain how you use estimation to check the reasonableness of a solution to a practical problem.
miskamm [114]

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7 0
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3 years ago
Subtract.<br> (4x + 7) - (x+1)<br> A. 3x + 8<br> B. 3x + 6<br> C. 4x + 8<br> O D. 4x + 6<br><br> Lmk
Studentka2010 [4]

Answer:

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Remove the bracket

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