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2 years ago

15

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

1 answer:

Anika [276]2 years ago

6 0

For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4

Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1

Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20

Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3

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2 years ago

After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?

beks73 [17]

Answer:

Percentage loss of the number of trees is $25\%$ .

Step-by-step explanation:

Given: After a storm, $135$ trees out of $180$ were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees $=180$

Number of trees left standing $=135$

Therefore, loss of trees $=180-135=45$

We now that $\text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%$

$\implies \text {Loss\%}=\frac{45}{180}\times 100 \%$

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$\implies \text {Loss\%}=25 \%$

Hence, the percentage loss of the number of trees is $25\%$ .

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2 years ago

A car purchased for $15,000 depreciates under a straight-line method in the amount of $950 each year. Which equation below best

alexandr1967 [171]

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3 years ago

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san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

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2 years ago

MATH ALGEBRA QUESTION

Alexxx [7]

Easy
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x^-m=1/(x^m)

so

f(-1)=4*7^-1=4*(1/(7^1))=4*(1/7)=4/7
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2 years ago

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