Question

What is an equation of the line that passes through the points (3,-3) and (-3,-3)?

Answer 1

First find the gradient of the line
Change in y/change in x
-3–3/-3-3
0/-6
=0 ( so the gradient m is equal to zero)

Y=0x+c

Input the coordinates of one point to find c

-3=(0*3)+c
-3=c


So the equation is
Y= -3