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2 years ago

WILL GIVE BRAINLIEST!

Mathematics

1 answer:

Brrunno [24]2 years ago

5 0

Answer:

The graph is not a function of x because x=0 intersects the graph at two points.

Step-by-step explanation:

The vertical line test is when you draw, well, a vertical line through the graph. the slope of a vertical line is undefined, and the formula written as x=_. So we can eliminate the choices with y=_.

We can clearly see that this graph isn't a function, so we can eliminate the answer choices that say that the graph is a function.

Just in case, draw a line at x=0, to check that it does indeed cross the graph in 2 places.

You might be interested in

Which number, when rounded to the nearest tenth, is 43.6? Options: A: 43.55 B: 43.657 C: 43.65 D: 43.549

weqwewe [10]

Answer:

A: 43.55

Step-by-step explanation:

Place value can be defined as the numerical value representing a digit owing to its position in a number. Some examples of the various place values used in representing each digit are tenths, hundredths, thousandths, unit, tens, hundreds, thousands etc.

For example, in the number 43.55;

The place value of 4 is tens.

The place value of 3 is units.

The place value of 5 is tenths.

The place value of 5 is hundredths.

Rounding up to the nearest tenth simply means to have 1 significant figure after the decimal point.

Therefore, 43.55 to the nearest tenth is 43.6

5 0

2 years ago

Read 2 more answers

A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu

Mars2501 [29]

Answer:

There can be at most $12$ attendees in a corporate team-building event.

Step-by-step explanation:

Let $x$ denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

$19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12$

So, there can be at most $12$ attendees in a corporate team-building event.

8 0

2 years ago

its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai

brilliants [131]

$T = \frac{-9}{2}x + 103$ is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

Solution:

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain

Given, when c = 6 thousand ft and $T = 76^{\circ}$ fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c ----- (ii)

Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain

Given, when c = 12 thousand ft and $T = 49^{\circ}$ fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

$c = \frac{-9}{2}$

Substituting the value of c in (ii) we get

$k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103$

Substituting the value of c and k in (i)

$T = \frac{-9}{2}x + 103$

Where "x" is in thousands of feet

Thus the required linear equation is found

5 0

2 years ago

Jorge needs a string that is 4 feet long. so far, his string is 44 inches. is it long enough or does he need to make it longer

dexar [7]

He needs it 4 inches longer because 4 ft is 48 inches.

5 0

3 years ago

Read 2 more answers

From its founding through 2012, the Rock and Roll Hall of Fame has inducted 303 groups or individuals. Forty-seven of the induct

motikmotik

The probability of inductees who are female will be 0.155.

<h3>How to illustrate the probability?</h3>

Question: What proportion of inductees have been female or have included female members?

From the information, 303 groups or individuals and forty-seven of the inductees have been female or have included female members.

Therefore, the proportion will be:

= 47/303

= 0.155

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

8 0

1 year ago