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3 years ago

WILL GIVE BRAINLIEST!

Mathematics

1 answer:

Brrunno [24]3 years ago

5 0

Answer:

The graph is not a function of x because x=0 intersects the graph at two points.

Step-by-step explanation:

The vertical line test is when you draw, well, a vertical line through the graph. the slope of a vertical line is undefined, and the formula written as x=_. So we can eliminate the choices with y=_.

We can clearly see that this graph isn't a function, so we can eliminate the answer choices that say that the graph is a function.

Just in case, draw a line at x=0, to check that it does indeed cross the graph in 2 places.

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if the survey, 9/25 of students ride the bus to school and 19/50 walk to school. what fraction of students ride the bus or walk

Elena-2011 [213]

1. $\dfrac{9}{25}$ of students ride the bus to school. Note that

$\dfrac{9}{25}=\dfrac{9\cdot 2}{25\cdot 2}=\dfrac{18}{50}.$

2. $\dfrac{19}{50}$ of students walk to school.

3. The fraction of students that ride the bus or walk to school is

$\dfrac{18}{50}+\dfrac{19}{50}=\dfrac{18+19}{50}=\dfrac{37}{50}.$

Answer: the fraction of students that ride the bus or walk to school is $\dfrac{37}{50}.$

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3 years ago

3x – y = -1 x – 2y = -12

Leviafan [203]

The solution to the system of equation is (2, 7)

<h3>System of equation</h3>

Given the system of equation expressed as:

3x – y = -1 * 2

x – 2y = -12 * 1

________________

6x – 2y = -2

x – 2y = -12

Subtract to have;

6x-x = -2-(-12)

5x = 10

x = 2

Substitute x = 2 into 2 to have:

2 - 2y = -12

-2y = -14

y = 7

Hence the solution to the system of equation is (2, 7)

Learn more on system of equation here: brainly.com/question/25976025

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1 year ago

Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w

Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

$\vec {v}=\left$

Now, the perimetric equations for initial point $(x_0,y_0,z_0)$ with direction vector $\vec{v}=\left$ , are

$x=x_0+at$

$y=y_0+bt$

$z=z_0+ct$

The initial point is (7,1,-5) and direction vector is $\vec {v}=\left$ . So the perimetric equations are

$x=(7)+(-4)t$

$x=7-4t$

Similarly,

$y=1+3t$

$z=-5+3t$

Therefore, the required perimetric equations are $x=7-4t, y=1+3t$ and $z=-5+3t$ .

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