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Mathematics

1 answer:

Brrunno [24]2 years ago

5 0

Answer:

The graph is not a function of x because x=0 intersects the graph at two points.

Step-by-step explanation:

The vertical line test is when you draw, well, a vertical line through the graph. the slope of a vertical line is undefined, and the formula written as x=_. So we can eliminate the choices with y=_.

We can clearly see that this graph isn't a function, so we can eliminate the answer choices that say that the graph is a function.

Just in case, draw a line at x=0, to check that it does indeed cross the graph in 2 places.

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Find p(2) for p(x)=x^4-2x^3-6x^2+5

Ede4ka [16]

(2)^4-2(2)^3-6(2)^2+5
16-64-144+5
-187

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2 years ago

Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi

zimovet [89]

Using the given endpoint R (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\$

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10$